16c^2-8c-35=0

Solution for 16c^2-8c-35=0 equation:

16c^2-8c-35=0

a = 16; b = -8; c = -35;
Δ = b2-4ac
Δ = -82-4·16·(-35)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-48}{2*16}=\frac{-40}{32}
=-1+1/4
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+48}{2*16}=\frac{56}{32}
=1+3/4
$